AI, Decision Making, and Probability

  • About decision-making

  • Uncertainty, likelihood, and probability

  • Decision-theoretic methods

Probability

  • Idea: chance and likelihood are important concepts for real reasoning

  • Method: assign probabilities to events and combinations of events

  • Reason from model using calculation

  • This is a general plan:

        Evidence -----------------> Conclusions
           |                            ^
           |                            |
           v                            |
         Model   -----------------> Extrapolation
    

Probability of Events

  • Domain: events

    • pr(E) is probability that event E happens

    • pr(E) = #E / (#E + #¬E)

    • For a coin pr(H) = #H / (#H + #T) = 1 / 2

    • For a pair of dice:

      • pr(R7) = #R7 / #R

      • #R7 = #{(1, 6), (2, 5), (3, 4), …} = 6

      • #R = #{D×D} = 36

      • pr(R7) = 6 / 36 = 1/6

      • Check with computer program prob7

Probability of Logical Situations

  • Domain: propositional formula

    • pr(p) is probability of logical combination of events

    • p is a prop formula

  • Priors and conditionals

    • pr(p|q) is prob of p given q (easy to get backward)

Axioms Of Probability

  • equivalence: if p ≡ q then pr(p) = pr(q)

  • range: 0 ≤ pr(p) ≤ 1

  • negation: pr(¬p) = 1 - pr(p)

  • conjunction: pr(p ∧ q) = pr(p) pr(q|p) = pr(q) pr(p|q)

Derived Probability Rules

  • disjunction: pr(p ∨ q) = pr(¬(¬p ∧ ¬q)) = 1 - pr(¬p ∧ ¬q)

  • Bayes's Rule:

      pr(q) pr(p|q) = pr(p ∧ q) = pr(p) pr(q|p)
      pr(q) pr(p|q) = pr(q|p) pr(p)
      pr(p|q) = pr(q|p) pr(p) / pr(q)
    

Independence

  • When p and q are conditionally independent pr(p|q) = pr(p)

    • By Bayes's Rule

      pr(q|p) = pr(p|q) pr(q) / pr(p)
              = pr(p) pr(q) / pr(p)
              = pr(q)
      
    • In this case, conjunction gets easier

      • pr(p ∧ q) = pr(p|q) pr(q) = pr(p) pr(q)
  • When p and q are strictly independent pr(p ∧ q) = 0

    • In this case, disjunction gets easier

      pr(p ∨ q)
      = 1 - pr(¬p ∧ ¬q)
      = 1 - pr(¬p) pr(¬q)
      = 1 - (1 - pr(p))(1 - pr(q))
      = 1 - (1 - pr(p) - pr(q) - pr(p) pr(q))
      = pr(p) + pr(q) + pr(p) pr(q)
      = pr(p) + pr(q)
      
Last modified: Monday, 26 October 2020, 11:29 PM